John Alexander vs Ron Holmberg Head to Head Tennis Stats and Match Analysis
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John Alexander and
Ron Holmberg have met 1 time. John Alexander currently holds the upper hand, leading the series 1β0.
Looking at their individual career profiles, John Alexander has compiled an overall career record of 591β434 across 1025 matches, translating to a win rate of 57.66%. On hard courts his record stands at 103β87 (54.21%), while on clay he holds a 225β132 (63.03%) mark. On grass the numbers read 153β96 (61.45%) , and on carpet 110β119 (48.03%). Throughout his career he has won 8 titles (3 hard, 2 clay, 2 grass, 1 carpet). Against Top 10 opponents his record reads 24β81 (22.86%).
Ron Holmberg, on the other hand, enters this matchup with a career mark of 51β73 from 124 matches (41.13% win rate). His hard-court record is 17β20 (45.95%), on clay he stands at 9β17 (34.62%), and on grass he has gone 18β18 (50.00%) , with a carpet record of 7β18 (28.00%). He has accumulated 1 title in total (1 grass).
When it comes to their head-to-head meetings, the surface breakdown reveals this contrast.
DateβΌ | Tourney | Surface | Round | Wrk | Winner | Lrk | Loser | Score | BoF | Min | WA | WDF | W1stIn | W1st% | W2nd% | BPSvd |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1972-04-09 | Quebec WCT | Carpet | R32 | - | - | 6-3 7-5 | 3 | - | - | - | - | - | - | 0/0 |