Alexander Zverev vs Paul-Henri Mathieu Head to Head Tennis Stats and Match Analysis

Alexander Zverev and Paul-Henri Mathieu have met 2 times. The series is tied 1–1.

Looking at their individual career profiles, Alexander Zverev has compiled an overall career record of 537–228 across 765 matches, translating to a win rate of 70.20%. On hard courts his record stands at 321–143 (69.18%), while on clay he holds a 171–62 (73.39%) mark. On grass the numbers read 45–23 (66.18%) . Throughout his career he has won 24 titles (15 hard, 9 clay). Against Top 10 opponents his record reads 58–83 (41.13%).

Paul-Henri Mathieu, on the other hand, enters this matchup with a career mark of 276–306 from 582 matches (47.42% win rate). His hard-court record is 127–147 (46.35%), on clay he stands at 108–114 (48.65%), and on grass he has gone 22–31 (41.51%) , with a carpet record of 19–14 (57.58%). He has accumulated 4 titles in total (2 clay, 2 carpet). Against Top 10 opponents his record stands at 10–59 (14.49%).

When it comes to their head-to-head meetings, the surface breakdown reveals this contrast. On hard courts they have met 1 times, with Paul-Henri Mathieu leading 1–0 (100.00%). On grass, their 1 encounter has yielded a record of 1–0 (100.00% for Alexander Zverev).